How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
136o
120o
108o
100o
96o
Correct answer is D
No explanation has been provided for this answer.
In the diagram above, AO is perpendicular to OB. Find x
7.5o
15o
22.5o
30o
38.6o
Correct answer is D
4x + 3x + 2x + 90 =360° [angle at a point]
9x + 90 = 360°
9x = 360° - 90°
9x = 270
x = 270/9
x = 30°
In the diagram above; O is the centre of the circle and |BD| = |DC|. If ∠DCB = 35°, find ∠BAO.
20o
25o
30o
35o
40o
Correct answer is A
< DBC = 35° (base angles of an isosceles triangle)
< CDB = 180° - (35° + 35°)
= 110°
< ADB = 70°; < ADB = 90°
\(\therefore\) < BAO = 180° - (70° + 90°)
= 20°
6 3/5cm
6 4/5cm
7 1/10cm
10 2/5cm
13 3/5cm,
Correct answer is E
Perimeter of sector = \(\frac{\theta}{360°} \times 2\pi r + 2r\)
= \(\frac{108}{360} \times 2 \times \frac{22}{7} \times \frac{7}{2} + 2(\frac{7}{2})\)
= \(6 \frac{3}{5} + 7\)
= \(13 \frac{3}{5} cm\)
31/2cm
7cm
1O1/2cm
14cm
21cm
Correct answer is B
The length of the arc subtended by the sector of angle 120° = circumference of the base of the cone.
\(\frac{120}{360} \times 2 \times \frac{22}{7} \times 21 = 2\pi r\)
\(44 = 2\pi r\)
\(r = 22 \div \pi\)
\(r = 22 \times \frac{7}{22}\)
r = 7 cm