How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
20m
40√3m/3
20√3m
40√3m
60cm
Correct answer is B
\(\tan 30 = \frac{x}{40}\)
\(x = 40 \tan 30 = \frac{40}{\sqrt{3}}\)
= \(\frac{40\sqrt{3}}{3} m\)
If sin x = 12/13, where 0° < x < 90°, find the value of 1 - cos\(^2\)x
25/169
64/169
105/169
144/169
8/13
Correct answer is D
\(\sin x = \frac{12}{13}\)
\(\cos x = \frac{5}{13}\)
\(\cos^{2} x = (\frac{5}{13})^2 = \frac{25}{169}\)
\(1 - \cos^{2} x = 1 - \frac{25}{169}\)
= \(\frac{144}{169}\)
cos 115o
cos 255o
cos 285o
-sin165o
-sin 255o
Correct answer is C
No explanation has been provided for this answer.
Given that tan x = 5/12, what is the value of sin x + cos x ?
5/13
7/13
12/13
17/13
5/12
Correct answer is D
\(\tan x = \frac{opp}{adj} = \frac{5}{12}\)
\(Hyp^2 = opp^2 + adj^2\)
\(Hyp^2 = 5^2 + 12^2\)
= \(25 + 144 = 169\)
\(Hyp = \sqrt{169} = 13\)
\(\sin x = \frac{5}{13}; \cos x = \frac{12}{13}\)
\(\sin x + \cos x = \frac{5}{13} + \frac{12}{13}\)
= \(\frac{17}{13}\)
20km
24km
25km
31km
84km
Correct answer is C
No explanation has been provided for this answer.