How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
| No. of Days | 1 | 2 | 3 | 4 | 5 | 6 |
| No. of students | 20 | 2x | 60 | 40 | x | 50 |
The distribution above shows the number of days a group of 260 students were absent from school in a particular term. How many students were absent for at least four days in the term?
180
120
110
40
Correct answer is B
20 + 2x + 60 + 40 + x + 50 = 260
170 + 3x = 260
3x = 260 - 170
3x = 90
x = 90/3 = 30
At least 4 days
4 days = 40
5 days = 30
6 days = 50
Total = 120
sec θ tan θ + k
tan θ + k
2sec θ + k
sec θ + k
Correct answer is B
∫sec2θ dθ = ∫ 1/cos2 dθ
∫(cos)-2 dθ,
let u = cos θ
∴∫u-2 = 1/u + c
∫cos θ = sin θ + c
∫sec-2θ = 1/u sin θ + c
= (sinθ / cosθ) + c
= Tan θ + c
2.3 cm
4.0 cm
5.2 cm
6.0 cm
Correct answer is B
S = t\(^3\) - t\(^2\) - t + 5
ds/dt = 3t\(^2\) - 2t - 1
As ds = 0
3t\(^2\) - 2t - 1 = 0
(3t+1)(t-1) = 0
∴ t = 1 or -1/3
At min pt t = 1
S = t\(^3\) - t\(^2\) - t + 5
put t = 1
= 1\(^3\) - \1(^2\) - 1 + 5
= 1 - 1 - 1 + 5
= 4
If s = (2 + 3t)(5t - 4), find ds/dt when t = 4/5 secs
0 units per sec
15 units per sec
22 unit per sec
26 units per sec
Correct answer is C
x = (2+3t)(5t-4)
Let u = 2+3t ∴du/dt = 3
and v = 5t-4 ∴dv/dt = 5
dx/dt = Vdu/dt + Udv/dt
= (5t-4)3 + (2+3t)5
= 15t - 12 + 10 + 15t
= 30t - 2
= 30x4/5 - 2
= 24 - 2
= 22
100m
75√3 m
100√3m
200√3m
Correct answer is C
| Tan 60 = | 300 |
| x |
| x = | 300 |
| Tan 60 |
| x = | 300 |
| √3 |
x = (300/√3) x (√3/√3)
| x = | 300√3 |
| .....3 |
x = 100√3