Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

2,246.

A tap supplies water at 26°C while another supplies water at 82°C. If a man wishes to bathe with water at 40°C, the ratio of hot water to that of cold water required is

A.

1:3

B.

3:1

C.

3:7

D.

7:3

E.

15:8

Correct answer is A

heat supplied by hot water = heat gained by cold water M1C(82 - 40) = M2C(40 - 26)

\(\frac{M_2}{M_1}\)= \(\frac{14}{42}\)

= 1: 3

2,247.

A team trap is a component of the apparatus used in determining the specific latent heat of vaporisation of steam. In the steady steady state, the steam trap

A.

stores the steam for future use

B.

prevents the steam from escaping

C.

ensures that only dry steam gets into the calorimeter

D.

allows condensed steam to go into the calorimeter

E.

determine the quantity of steam used

Correct answer is C

No explanation has been provided for this answer.

2,248.

The boiling point of a liquid depends on the following except the

A.

nature of the liquid

B.

external pressure

C.

volume of the liquid

D.

impurities present in the liquid

E.

degree of it's molecular cohesive force

Correct answer is C

No explanation has been provided for this answer.

2,249.

A fixed mass of gas of volume 600cm3 at a temperature of 27oC is cooled at constant pressure to a temperature of 0oC. What is the change in volume?

A.

54cm2

B.

273cm2

C.

300cm2

D.

546cm2

E.

600cm2

Correct answer is A

\(\frac{V_1}{T_1} = \frac{V_2}{T_2}\)

T2 = 0 + 273 = 273k

V1 = 600

T1 = 27 + 273 = 300k

V2 = \(\frac{V_1T_2}{T_1}\) = 546cm

V1 - V2 = 54cm

2,250.

The set-up illustrated above shows a capillary tube of uniform cross-sectional area in two different arrangements. Using the data in the diagrams. Calculate the pressure of the atmosphere

A.

76cm of Hg

B.

75cm of Hg

C.

74cm of Hg

D.

60cm of Hg

E.

45cm of Hg

Correct answer is B

P1 = p + 15, p2 = p - 15

v1 = 30cm, v2 = 45cm

P1v1 = p2v2

p = 75cm of Hg