Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,611.

A lamp is marked 220V 60 W. Calculate the energy it would consume when connected to a 220V source for 1 hour.

A.

216000J

B.

13200J

C.

3600J

D.

864J

E.

220J

Correct answer is A

E = pt
=> 60 x 1 x 60 x 60 = 216000J

3,612.

It takes 4 minutes to boil a quantity of water electrically. How long will it take to boil same quantity of water using the same heating coil but with the current doubled? (neglecting any external heat loss).

A.

64 minutes

B.

32 minutes

C.

8 minutes

D.

2 minutes

E.

1 minute

Correct answer is E

D ∝ l2
E will increase 4 times when current is doubled.
Therefore time will decrease by a factor of 4, which is 1 minute.

3,613.

Two parallel conductors carry equal currents in the same direction. Which of the following statement is not a correct observation?

A.

Each of teh conductors will experience a force

B.

Each of the conductors can move

C.

The forces on the conductors will be equal

D.

There are concentric lines of force around each conductor

E.

The two conductors will repel each other

Correct answer is E

No explanation has been provided for this answer.

3,614.

A cell can supply current of 0.8A and 0.4A through a 2Ω and a 3Ω resistors respectively. Calculate the internal resistance of the cell.

A.

0.2Ω

B.

0.4Ω

C.

1.0Ω

D.

3.0Ω

E.

9.0Ω

Correct answer is C

Assume the internal resistor = R

Current with 2 Ohm Resistor = 0.80A

Voltage = (R + 2) x 0.80 = V ; That is 0.8R + 1.6 = V ———————[[1]

Current with 3 Ohm Resistor = 0.40 A

Voltage = (R+3) x 0.40 = V ; That is 0.4R + 1.2 = V ————————[[2]

Subtracting 1 from 2 gives

--> (0.8 - 0.4) R 

     ( 1.6 - 1.2 ) 

     ( V - V ) 

Therefore 

0.4R  + 0.4 = 0

R = 0.4 /0.4 = 1 Ohms

3,615.

Local action is normally prevented from taking place in a simple electric cell by

A.

introducing an oxidising agent into the acid

B.

not drawing current continuously for long periods

C.

amalgamating the surface of the zinc plate

D.

using a porous pot to isolate the zinc plate from the acid

E.

using dilute sulphuric acid

Correct answer is C

No explanation has been provided for this answer.