Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,816.

An object of mass 80 kg is pulled on a horizontal rough ground by a force of 500 N. Find the coefficient of static friction.
[g = 10 ms-2]

A.

0.8

B.

0.4

C.

1.0

D.

0.6

Correct answer is D

coefficient of friction

= \(\frac{F}{R}\)

=\(\frac{F}{mg}\)

 = \(\frac{500}{80 \times 10}\)
= 0.625

3,817.

If a cage containing a truck of coal weighing 750 kg is raised to a height of 90 m in a minute, what is the total power expended?
[g = 10 ms2]

A.

11.50 kw

B.

12.60 kw

C.

11.25 kw

D.

12.10 kw

Correct answer is C

Power = \(\frac{work done}{time taken}\)

where 1 min = 60s

= \(\frac{mgh}{t}\)
= \(\frac{750 \times 10 \times 90}{60}\)

= 11250w or 11.25kw

3,818.

I. The motion of the tyres of a moving car.
II. The motion of a loaded test tube oscillated
vertically.
III. The beating of the heart.
IV. A stone tied to a string and whirled round.
V. The motion of the pistons in a gasoline engine.
Which of the motions above is simple harmonic?

A.

III, IV and V only

B.

II, III and V only

C.

II, III and IV only

D.

I,II and III only

Correct answer is B

Simple harmonic motion is the motion of a body whose acceleration is directed towards a fixed point and is directly proportional to its displacement from point.

Statements ii, iii and v are clear examples

3,819.

A bullet fired vertically upward from a gun held 2.0 m above the ground reaches its maximum height in 4.0s. calculate its initial velocity.

[g = 10ms-2]

A.

10 ms-1

B.

8 ms-1

C.

40 ms-1

D.

20 ms-1

Correct answer is C

At maximum height, the final velocity, v = 0
thus from v = u - gt
0 = u - gt
∴ U = at = 10 x 4 = 40 mls

3,820.

What is the acceleration between two points on a velocity time graph which has coordinates
(10s, 15 ms-1)
and (20 s, 35 ms-1)?

A.

1.7 ms-2

B.

3.50 ms-2

C.

1.00 ms-2

D.

2.00 ms-2

Correct answer is D

Acceleration = \(\frac{ΔV}{Δt}\)

= \(\frac{V - U}{t_2 - t_1}\)

= \(\frac{35 - 15}{20 - 10}\)

= \(\frac{20}{10}\)

= 2ms\(^-2\)