Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

3,861.

A radioactive substance has a half life of 20 days. What fraction of the original radioactive nuclei will remain after 80 days?

A.

\( \frac{1}{32} \)

B.

\( \frac{1}{16} \)

C.

\( \frac{1}{8} \)

D.

\( \frac{1}{4} \)

Correct answer is B

80 days = 4 half lives (i.e 4 x 20dqs = 80dq)

But the fraction always left by any radioactive material after 4 half lives is

\( \left ( \frac{1}{2} \right)^4 = \frac{1}{16} \)

3,862.

A 120 V, 60 W lamp is to be operated on 220 V a.c. the supply mains. calculate the values of non-inductive resistance that would be required to ensure that the lamp is run on current value.

A.

100 Ω

B.

200 Ω

C.

300 Ω

D.

500 Ω

Correct answer is B

Power of the lamp = 60W = (V2)/R and the voltage rate = 120v.
R = (V2)/60 = (120 X 120)/60 = 240 Ω, the fuse wire that should ensure current does not exceed this value should be rated 200 Ω

3,863.

The instrument that measures both a.c and d.c is?

A.

a current balance

B.

a moving current ammeter

C.

a moving iron ammeter

D.

an inverter

Correct answer is C

No explanation has been provided for this answer.

3,864.

A 40 kW electric cable is used to transmit electricity through a resistor of resistance 2.0Ω at 800 V. The power loss as internal energy is?

A.

4.0 x 102W

B.

5.0 x 102W

C.

4.0 x 103W

D.

5.0 x 103W

Correct answer is D

In general, power = IV; 40kw = IV.
∴ 40,000 = 1 x 800
1 = (40.000)/800 = 50A. tune the current through resistor = 50A.
∴ power loss = 12R = 502 X 2 = 2500 X 2 = 5.0 X 103W

3,865.

A conductor has a diameter of 1.00 mm and length 2.00m. if the resistance of the material is 0.1Ω, its resistivity is?

A.

2.55 x 105 Ωm

B.

2.55 x 102 Ωm

C.

3.93 x 10-6 Ωm

D.

3.93 x 10-8 Ωm

Correct answer is D

R = (1)/a, P = (R.a)/1 = (0.1 x 3.14)/2 (10-3/2)3
∴ P = (0.1 x 3.14 x 10-6)/2 x 4
= 0.3925 x 10-7 OR -3.930 X 10-8 Ωm