Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

4,061.

Calculate the refractive index of the material for the glass prism in the diagram above

A.

√2/2

B.

4/3

C.

√2

D.

3/2

Correct answer is C

n = sin((A+D)/2)
sin(A/2)

where A = the refracting angle of the prism(60o)
D = angle of deviation of the ray (30o)
n = sin((60+30)/2)
sin(60/2)

= sin 45
sin 30

=
1/√2/1/2
√2/2/1/2
= √2/2 x 2/1 = √2
n = √2

4,062.

The diagram above shows the force (F) acting on an object through a distance (x). The work done on this object is expressed as

A.

Fx J

B.

Fx/2 J

C.

Fx2 J

D.

F/x J

Correct answer is B

The work done on this object is given by the area of the triangle, which is equal to 1/2 fx

4,063.

The diagram above show s the force-extension curve of a piece of wire. The energy stored when the wire is stretched from E to F is?

A.

7.5 x 10-3J

B.

2.5 x 10-3J

C.

1.5 x 10-2J

D.

7.5 x 10-1J

Correct answer is D

Energy store is equal to the work done in stretching the wire from E to F given by the area of the shaded trapezium under the graph.
= 1/2(0.1 x 0.2) x (0.1 - 0.05)
= 1/2(0.3) x 0.05
= 0.15 x 0.05
= 0.075
= 7.5 x 10-1J

4,064.

In the diagram above, determine the r.m.s current

A.

31A

B.

48A

C.

60A

D.

80A

Correct answer is B

Ir.m.s = Vr.m.s/Z
But Z =
 R2 + XL2 

=
 42 + 32 

=
 16 + 9 

=
 25 

∴Ir.m.s = 240/5
= 48.0A

4,065.

In the circuit diagram above , the ammeter reads a current of 3A when R is 5Ω and 6A when R is 2Ω. Determine the value of x

A.

B.

C.

10Ω

D.

Correct answer is C

for a parallel R and X, when R = 5Ω,

effective resistance R = 5X
5+X


and when R = 2Ω

 

effetive resistance R = 2X
2+X


Thus since E = I(R+r), and if r = 0 then E = IR
∴(i) E = 3(5X/(5+x)); (ii) E = 6(2X(2+x))
∴3(5X/(5+X)) = 6(2X/(2+X))
=> (5X/(5+X)) = 2(2x/(2+X))
∴ (5X/(5+X)) = (4X/(2+X))
5x(2+x) = 4x(5+x)
10x + 5x2 = 20x + 4x2
5x2 - 4x2 = 20x - 10x
=>x2 = 10x
∴x2 - 10x = 0
x(x - 10) = 0
∴ x = 0 or 10
∴ x = 10Ω