Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

4,116.

A wheel and axle is used to raise a load of 500 N by the application of an effort of 250 N. If the radii of the wheel and the axle are 0.4 cm and 0.1 cm respectively, the efficiency of the machine is

A.

20 %

B.

40 %

C.

50 %

D.

60 %

Correct answer is C

Efficiency = M.A/V.R X 100/1 M.A = Load/Effort = 500/250
= 2
V.R. = radius of wheel/radius of axle = 0.4/0.1 = 4.
therefore Efficiency = 2/4 x 100/1 = 50 %

4,117.

A copper cube weighs 0.25 N in air, 0.17N when completely immersed in paraffin oil and 0.15 N when completely immersed in water.The ratio of upthrust in oil to upthrust in water is

A.

3 : 5

B.

4 : 5

C.

7 : 10

D.

13 : 10

Correct answer is B

Wt. in air = 0.25 N
Wt.in water = 0.15 N
therefore lost in wt. in water = Upthrust in water
= 0.25 - 0.15
= 0.10 N.
Wt. in paraffin oil = 0.17 N.
.. loss in wt.in oil = upthrust in the oil
Ratio upthrust in oil to upthrust in water
= 0.18/0.10 = 8/10 = 4/5 Or 4 : 5

4,118.

The magnetic force on a charged particle moving with velocity v is

A.

proportional to both the magnitude of the charge and the velocity v

B.

independent of the magnitude of the charge

C.

proportional to the velocity v only

D.

proportional to the magnitude of the charge only

Correct answer is A

The magnetic force on a charge is given by
F = qVB Sinθ,
thus the force is proportional to both the magnitude by the charge (q) and the velocity (V)
(i/e F α qV)

4,119.

A capacitor of 20 x 10-12F and an inductor are joined in series. The value of the inductance that will give the circuit a resonance frequency of 200kHz is

A.

I/16 H

B.

I/8 H

C.

I/64 H

D.

I/32 H

Correct answer is D

Resonant, frequency in an a.c. circuit is given by F = I/2π√LC
therefore 200 * 103 = I/2 * π√l * 20 * 10-12
therefore (2.0 * 105)2 = I/4 * π2 * L * 20 * 10-12
THEREFORE L = I/4.0 * 1010 * 4 * 10 * 20 * 10-12
(if π2 = 10)
= I/16 * 1011 * 2.0 * 10-11
Therefore L = I/32 H

4,120.

Energy losses through eddy currents are reduced by using

A.

low resistance wires

B.

insulated soft iron wires

C.

few turns of wires

D.

high resistance wires

Correct answer is B

No explanation has been provided for this answer.