17.3\(ms^{-2}\)
20\(ms^{-2}\)
24.5\(ms^{-2}\)
125\(ms^{-2}\)
200\(ms^{-2}\)
Correct answer is B
\(v^2=u^2 +2as =0 +2\times(25-5)\\ v^2 =0+20\times 20=400;v =\sqrt{400}= 20(ms^{-2}\)
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