2.4 x\(10^{-2}cm^{-3}\)
1.6 x\(10^{-2}cm^{-3}\)
8 x\(10^{-2}cm^{-3}\)
5 x\(10^{-2}cm^{-3}\)
4 x\(10^{-2}cm^{-3}\)
Correct answer is A
\(3{\alpha}= \frac{\Delta{V}}{V_1\Delta{T}}\Rightarrow \frac{\Delta{V}}{100\times40}=3\alpha\, where\, \alpha = 2 \times 10^{-6}\\ \frac{\Delta{V}}{4000}=6\times10^{-6}\Rightarrow \Delta=4\times10^3\times6\times10^{-6}= 2.4\times10^{-2}cm^{-3}\)
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