0.001A
0.011A
0.111A
1A
1.1A
Correct answer is C
m=zIt, \(I=\frac{m}{zt}= \frac{6.6\times10^{-4}}{3.3 \times10^{-7}\times 1800}=1.1111\\ \)error=1.1111-1.0=0.111A.
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