9 x \(10^{7}\)J
1.8 x \(10^{8}\)J
1.8 x \(10^{9}\)J
9 x \(10^{-10}\)J
3.6 x \(10^{11}\)J
Correct answer is B
E=\(mc^2 = 2\times10^{-6} \times10^{-3}\times(3\times10^{8})^2=1.8\times10^{8}\)
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