In the diagram above, AB//CD, the bisector of ∠BAC an...
In the diagram above, AB//CD, the bisector of ∠BAC and ∠ACD meet at E. Find the value of ∠AEC
30o
45o
60o
75o
90o
Correct answer is E
Ae is a bisector of BAC => EAC = 45o
CE is the bisector of ACD => ACE = 45o
AEC = 180o - [EAC + ACE]
= 180o - (45o + 45o) = 180o - 90o = 90o
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