In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC ...
In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD
A.
50o
B.
60o
C.
65o
D.
100o
E.
115o
Correct answer is E
ACB = ABC [Base angles of isoceles triangle]
ACB + ABC + 50o = 180o[sum of angles in a triangle]
ACB + ABC = 180o - 50o = 130o
ACB
130o2
= 65oACD + ACB = 180o[sum of ∠s on a straight line]
ACD + 65o = 180o
ACD = 180o - 65o = 115o
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