6.0x10-1T
6.0x10T
6.0x10-3T
6.0x10-4T
Correct answer is B
B = \(\frac{F}{QV}\)
B = \(\frac{1.8 \times 10^{-8}}{1.0 \times 10^{-8} \times 3.0 \times 10^{-2}}\)
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