1.1 x 10-5N
3.3 x 10-5N
3.0 x 10-4N
9.0 x 10-4N
Correct answer is D
F \(\alpha \frac{1}{r^2}\)
therefore, \(\frac{F_1}{F_2}\) = \(\frac{r_1}{(r_2)^2}\)
\(\frac{10^{-4}}{F_2}\) = \(\frac{(0.06)^2}{(0.18)^2}\)
F = 9 x 10-4N
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