58o
68o
78o
90o
112o
Correct answer is D
considering SPQ
S = 34o (base ∠s of Isos. Δ)
P = 180o - 68o = 112o
R = 122/2 = 56o
a = 34o (alt ∠s)
SQR = 180o - (56 + 34)
180o - 90o = 90o
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