A platinum resistance thermometer records 3.0\(\Omega\) at 0^oC and 8.0\(\Omega\) at 100^oC. If it records 6.0\(\Omega\) in a certain environment, The temperature of the medium is

80^oC

60^oC

50^oC

30^oC

Correct answer is B

8\(\Omega\).....100^oC

6\(\Omega\).....\(\theta\)^oC

3\(\Omega\).....0^oC

\(\frac{6 - 3}{8 - 3}\) = \(\frac{\theta - 0}{100 - 0}\)

therefore, \(\theta\) = 60^oC

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