The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 10⁹Nm²C^-2]

1.8 x 10^-10N

9.0 x 10^-8N

9.0 x 10²N

4.5 x 10³N

Correct answer is C

F =\(\frac{1}{4{\pi}{\varepsilon}_o}\) x \(\frac {q_1q_2}{r^2}\)

F =\(\frac {5 {\times} 10 {\times} 8 {\times} 10}{0.002 {\times} 0.002}\) x 9 x 10

F = 900N

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The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 10⁹Nm²C^-2]

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The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 109Nm2C-2]

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The force of repulsion between two point positive charges 5\(\mu\)C and 8\(\mu\)C separated at a distance of 0.02 map art is. [\(\frac{1}{4{\pi}{\varepsilon}_o}\) = 9 x 10⁹Nm²C^-2]