\(\frac{1}{36}\)
\(\frac{1}{6}\)
\(\frac{1}{3}\)
\(\frac{1}{2}\)
\(\frac{2}{3}\)
Correct answer is B
When the die is rolled, occasion of getting 4
P(obtaining a 4) = \(\frac{1}{6}\)
= \(\frac{1}{6}\)
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