The energy contained in a wire when it extended by 0.02m ...
The energy contained in a wire when it extended by 0.02m by a force 500 N is
5J
10J
103J
104
Correct answer is A
Energy = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 500 x 0.02
E = 5J
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