The energy contained in a wire when it extended by 0.02m ...
The energy contained in a wire when it extended by 0.02m by a force 500 N is
5J
10J
103J
104
Correct answer is A
Energy = 12Fe
= 12 x 500 x 0.02
E = 5J
n = α 0.06eV E=3 -1.6eV E=2 -3.7eV E=1 -5.5eV E=0 -10.4eV ...
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