In the diagram, AB is a vertical pole and BC is horizonta...
In the diagram, AB is a vertical pole and BC is horizontal. If |AC| = 10m and |BC| = 5m, calculate the angle of depression of C from A
63o
60o
45o
27o
Correct answer is B
In triangle ABC, BCAC=cosθ
⟹cosθ=510=0.5
\theta = \cos^{-1} (0.5) = 60°
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