In the diagram, POS and ROT are straight lines, OPQR is a...
In the diagram, POS and ROT are straight lines, OPQR is a parallelogram. |OS| = |OT| and ∠OST = 50°. Calculate ∠OPQ.
160o
140o
120o
100o
Correct answer is D
< T = < S = 50° (OS = OT)
< SOT = 180° - 2(50°) = 80°
< ROP = 80° (vertically opposite angle)
\(\therefore\) < OPQ = 180° - 80° = 100° (adjacent angles)
Similar Questions
Find the value of α2 + β2 if α + β = 2 and the distance between points (1, &al...
Simplify 1¼ ÷ (2 ÷ ¼ of 28)...
Find the sum of the first 20 terms of the series 8, 12, 16, ....., 96 ...
For what values of x is the curve y = \(\frac{x^2 + 3}{x + 4}\) decreasing?...
The graph of 2y = 5x2 - 3x2 - 2 cuts the y axis at the point...
Solve the equation \(\frac{2y-1}{3} - \frac{3y-1}{4} = 1\) ...
The area of a circle of radius 4cm is equal to (Take π = 3.142 ) ...
The population of a village is 5846. Express this number to three significant figures ...