An object of mass 400g and density 600kgm^-3 is suspended with a sting so that half of it is immersed in paraffin of density 900kgm^-3. The tension in the string is

1.0N

3.0N

4.0N

5.0N

Correct answer is B

volume of object = \(\frac{400 \times 10^{-2}}{600}\)

= 0.00067m³

volume of paraffin displaced = \(\frac{1}{2}\) x 0.00067

= 0.00034m³

mass of paraffin = 900 x 34 x 10^-5

= 0.3kg

weight of paraffin = 0.3 x 10

= 3N = upthrust = tension in the string

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