An element X of an atomic number 88 and mass number 226 d...
An element X of an atomic number 88 and mass number 226 decays to form an element Z by emitting two beta particles and an alpha particle. Z is represented by
22282Z
22288Z
22686Z
22680Z
Correct answer is B
22688X → (0−1e) + 42α + baX
a + 2 + (-2) = 88 a ⇒ a = 88
b + 4 + 0 = 266 b ⇒ b = 222
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