Given that sin P=513, where p is acute, find ...
Given that sin P=513, where p is acute, find the value of cos p - tan p
A.
79156
B.
85156
C.
713
D.
81
Correct answer is A
If sinP=513 from right angled triangle from pythagoras theorem
BC^2 = 13^2 - 5^2\\
=169-25\\
BC = \sqrt{144} = 12\\
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}\\
=\frac{79}{156}
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