Which of the following apparatus will require the smalles...
Which of the following apparatus will require the smallest fuse rating for its protection?
60W, 240V
60W, 40V
40W, 12V
40W, 5V
Correct answer is A
I = \(\frac{P}{V}\) = \(\frac{60}{240}\) = 0.25A
I = \(\frac{P}{V}\) = \(\frac{60}{40}\) = 1.5A
I = \(\frac{P}{V}\) = \(\frac{40}{12}\) = 3.3A
I = \(\frac{P}{V}\) = \(\frac{40}{5}\) = 8A