A light wave of frequency 5 x 10¹⁴Hz moves through water which has a refractive index of \(\frac{4}{3}\). Calculate the wavelength in water if the velocity of light in air is 3 x 10⁸ms^-1

4.5 x 10^-7m

6.0 x 10^-7m

1.7 x 10⁶m

2.2 x 10⁶m

Correct answer is A

\(\frac{1}{4}\) = \(\frac{3 \times 10}{v}\)

v = 2.25 x 10⁸ms^-1

\(\lambda\) = \(\frac{V}{F}\)

= \(\frac{2.25 \times 10^8}{5 \times 10^14}\)

\(\lambda\) = 0.45 x 10^-6m

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