A light wave of frequency 5 x 10¹⁴Hz moves through water which has a refractive index of $\frac{4}{3}$ . Calculate the wavelength in water if the velocity of light in air is 3 x 10⁸ms^-1

4.5 x 10^-7m

6.0 x 10^-7m

1.7 x 10⁶m

2.2 x 10⁶m

Correct answer is A

$\frac{1}{4}$ = $\frac{3 \times 10}{v}$

v = 2.25 x 10⁸ms^-1

$\lambda$ = $\frac{V}{F}$

= $\frac{2.25 \times 10^8}{5 \times 10^14}$

$\lambda$ = 0.45 x 10^-6m

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