In the diagram, |QR| = 10cm, PR⊥QS, angle PSR = 30&d...
In the diagram, |QR| = 10cm, PR⊥QS, angle PSR = 30° and angle PQR = 45°. Calculate in meters |QS|
10(1+√3)
20√3
10√3
(10+√3)
Correct answer is A
In Δ PQR,
tan45=PR10⟹PR=10tan45
= 10m
In Δ PRS,
tan30=10RS⟹RS=10tan30
= 10{1√3
= 10√3
PS = 10+10√3
= 10(1+√3)cm
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