A right circular cone is such that its radius r is twice ...
A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h
\(\frac{2}{3}\pi h^2\)
\(\frac{1}{12}\pi h^3\)
\(\frac{4}{3}\pi h^2\)
\(\frac{4}{3}\pi h^3\)
Correct answer is D
Volume of a cone = \(\frac{\pi r^2 h}{3}\)
r = 2h.
V = \(\frac{\pi \times (2h)^2 \times h}{3}\)
= \(\frac{4}{3} \pi h^3\)
Find the value of x in the equation 3x\(^2\) - 8x - 3 = 0...
If \(\frac{x}{a+1}+\frac{y}{b}\) 1. Make y the subject of the relation...
Simplify \((\sqrt[3]{64a^{3}})^{-1}\) ...
Solve for x in \(\frac{4x - 6}{3} \leq \frac{3 + 2x}{2}\)...
Make L the subjects of the formula if \(\sqrt{\frac{42w}{5l}}\) ...