A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s^-1, the angular speed of the larger wheel is

3 rev s^-1

40 rev s^-1

360 rev s^-1

2400 rev s^-1

Correct answer is C

$\frac{\text {speed of driver}}{\text {speeder driven}}$ = $\frac{\text {no. of teeth of driver}}{\text {no. of teeth of driven}}$

$\frac{120}{V}$ = $\frac{20}{60}$

v = 360 rev s^-1

See all Physics questions & answers

See more JAMB questions & answers

A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s^-1, the angular speed of the larger wheel is

Similar Questions

Aptitude Tests

A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s-1, the angular speed of the larger wheel is

Similar Questions

Aptitude Tests

A 20-toothed gear wheel drives a 60-toothed one. If the angular speed of the smaller wheel is 120 rev s^-1, the angular speed of the larger wheel is