A force, 10N, drags a mass 10kg on a horizontal table wit...
A force, 10N, drags a mass 10kg on a horizontal table with an acceleration of 0.2ms. If the acceleration due to gravity is 10ms-1, the coefficient of friction between the moving mass and the table is
0.02
0.08
0.20
0.80
Correct answer is B
μmg = ma
μmg = F - ma
μ x 10 x 10 = 10 - (10 x 0.2)
100 μ =10 - 2
dividing both sides by 100
μ = 8 / 100
μ = 0.08
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