3a+b
a−3ba2−b2
\frac{3a-b}{a^2 – b^2}
\frac{a-3b}{a^2+b^2}
Correct answer is B
Simplify \frac{2}{a+b}-\frac{1}{a-b}; \frac{2(a-b)-1(a+b)}{(a+b)(a-b)}
= \frac{2a-2b-a-b}{(a+b)(a-b)}
= \frac{a-3b}{a^2 - ab + ab - b^2}
= \frac{a-3b}{a^2-b^2}
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