1.4ϖcm2
2.8ϖcm2
4.9ϖcm2
9.8ϖcm2
Correct answer is C
Area of a sector \(=\frac{\theta}{360}\times \pi r^2\\
\left(\frac{144}{360}\times \pi \times \frac{3.5}{1} \times 3.5\right)cm^2 = 4.9\pi cm^2\)
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