A galvanometer of resistance 5.0Ω has full-sca...
A galvanometer of resistance 5.0Ω has full-scale deflection for a current of 100mA. How would its range be extended to 1.0A? By placing a resistance of
59Ω in parallel
95Ω in series
45Ω in parallel
45Ω in series
95Ω in parallel
Correct answer is A
Given Data:
Ig = 100ma = 0.1A
Rg=5
where Is = I - Ig → 1 - 0.1
Is = 0.9
IgRg = IsRs
0.1 * 5 = 0.9 * Rs
Rs = 0.1∗50.9
Rs = 59
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