4
1
-1
-4
Correct answer is D
y = x2 - 2x - 3,
Then δyδx=2x−2
But at minimum point,δyδx=0,
Which means 2x - 2 = 0
2x = 2
x = 1.
Hence the minimum value of y = x2 - 2x - 3 is;
ymin = (1)2 - 2(1) - 3
ymin = 1 - 2 - 3
ymin = -4
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