$\begin{array}{c|c} Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency & 18 & 22 & 20 & 16 & 10 & 14 \end{array}$

The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?

$\frac{1}{5}$

$\frac{1}{2}$

$\frac{2}{5}$

$\frac{3}{4}$

Correct answer is C

Let E demote the event of obtaining at least a 4
Then n(E) = 16 + 10 + 14 = 40

Hence, prob (E) = $\frac{n(E)}{n(S)}$

$= \frac{40}{100}$

$= \frac{2}{5}$

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$\begin{array}{c|c} Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency & 18 & 22 & 20 & 16 & 10 & 14 \end{array}$

The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?

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$\begin{array}{c|c} Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline Frequency & 18 & 22 & 20 & 16 & 10 & 14 \end{array}$

The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?