t + 1
2t
2t + 1
t
Correct answer is B
\(\sum x\) = (t + 2) + (2t + 4) + (3t + 2) + 2t = 8t
N = 4_
∴ Mean, x = \(\frac{\sum x}{N} = \frac{8t}{4} = 2t\)
= 2t
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