\(\frac{5!}{3!}\)
\(\frac{5!}{2!2!}\)
\(\frac{5!}{2!3!}\)
\(\frac{5!}{2!}\)
Correct answer is C
A student can select 2 subjects from 5 subjects in;
5C3 ways, i.e. = \(\frac{5!}{2!(5 - 2)!}\)
= \(\frac{5!}{2!3!}\)
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