2√6
4√6
8√6
16√6
Correct answer is C
(√6+2)2−(√6−2)2
= [(√6+2)+(√6−2)][(√6+2)−(√6−2)]
= (√6+2+√6−2)(√6+2−√6+2)]
= (2√6)(4)
= 8√6
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