2√6
4√6
8√6
16√6
Correct answer is C
(√6+2)2−(√6−2)2 = [(√6+2)+(√6−2)][(√6+2)−(√6−2)] = (√6+2+√6−2)(√6+2−√6+2)] = (2√6)(4) = 8√6
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