1c(w−2vv+w)
1c(w−2vv−w)
1c(w+2vv−w)
1c(w+2vv+w)
Correct answer is A
w = v(2+cn)1−cn
2v + cnv = w(1 - cn)
2v + cnv = w - cnw
2v - w = -cnv - cnw
Multiply through by negative sign
-2v + w = cnv + cnw
-2v + w = n(cv + cw)
n = −2v+wcv+cw
n = 1c−2v+wv+w
Re-arrange...
n = 1cw−2vv+w
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