Find the equation of a line perpendicular to line 2y = 5x...
Find the equation of a line perpendicular to line 2y = 5x + 4 which passes through (4, 2).
5y - 2x -18 = 0
5y + 2x - 18 = 0
5y - 2x + 18 = 0
5y + 2x - 2 = 0
Correct answer is B
2y = 5x + 4 (4, 2)
y = 5x2 + 4 comparing with
y = mx + e
m = 52
Since they are perpendicular
m1m2 = -1
m2 = −1m1 = -1
52 = -1 x 25
The equator of the line is thus
y = mn + c (4, 2)
2 = -25(4) + c
21 + 85 = c
c = 185
y = -25x + 185
5y = -2x + 18
or 5y + 2x - 18 = 0
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