sec2 θ
tan θ cosec θ
cosec θsec θ
cosec2θ
Correct answer is A
sinθcosθ cosθd(sinθ)dθ−sinθd(cosθ)dθcos2θ cosθ.cosθ−sinθ(−sinθ)cos2θ cos2θ+sin2θcos2θ Recall that sin2 θ + cos2 θ = 1 1cos2θ = sec2 θ
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