1, -2, 3
1, 2, -3,
-1, -2, 3
-1, 2, -3
Correct answer is A
Equation: x3 - 2x2 - 5x + 6 = 0.
First, bring out an which is the coefficient of x3 = 1.
Then, a0 which is the coefficient void of x = 6.
The factors of an = 1; The factors of a0 = 1, 2, 3 and 6.
The numbers to test for the roots are ±(a0an).
= ±(1,2,3,6).
Test for +1: 13 - 2(12) - 5(1) + 6 = 1 - 2 - 5 + 6 = 0.
Therefore x = 1 is a root of the equation.
Using long division method, x3−2x2−5x+6x−1 = x2 - x - 6.
x2 - x - 6 = (x - 3)(x + 2).
x = -2, 3.
∴ The roots of the equation = 1, -2 and 3.
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