2, 3
3, 2
-2, -3
-3, -2
Correct answer is C
log4(y - 1) + log4(12x) = 1
log4(y - 1)(12x) → (y - 1)(12x) = 4 ........(1)
log2(y + 1) + log2x = 2
log2(y + 1)x = 2 → (y + 1)x = 22 = 4.....(ii)
From equation (ii) x = 4y+1........(iii)
put equation (iii) in (i) = y (y - 1)[12(4y−1)] = 4
= 2y - 2
= 4y + 4
2y = -6
y = -3
x = 4−3+1
= 4−2
X = 2
therefore x = -2, y = -3
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