0.36
0.46
0.56
0.76
0.86
Correct answer is C
Heat lost = heat gained
moCo\(\theta\)o = mwCw\(\theta\)w
100 x Co x (25 - 9) = 150 x Cw x (15 - 9)
\(\frac{C_w}{C_w}\) = 0.56
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