π2, 3π2
π3, 2π3
0, π3
0, π
Correct answer is D
cos x + sin x 1cosx−sinx
= (cosx + sinx)(cosx - sinx) = 1
= cos2x + sin2x = 1
cos2x - (1 - cos2x) = 1
= 2cos2x = 2
cos2x = 1
= cosx = ±1 = x
= cos-1x (±, 1)
= 0, π 32π, 2π
(possible solution)
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