1 + x sec x tan x
1 + sec2 x
cos x + x tan x
x sec x tan x + secx
Correct answer is D
let y = xcosx = x sec x
y = u(x) v (x0
dydx = Udydx + Vdudx
dy x [secx tanx] + secx
x = x secx tanx + secx
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