\(\frac{13}{9}\)
1
\(\frac{1}{3}\)
\(\frac{1}{9}\)
Correct answer is A
Tn = 31 - n
S3 = 31 - 1 + 31 - 2 + 31 - 3
= 1 + \(\frac{1}{3}\) + \(\frac{1}{9}\)
= \(\frac{13}{9}\)
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